What is the tangent of y=sqrt(2x+1),\at x= 1/2 ?

The tangent of y=sqrt(2x+1),\at x= 1/2 is y= 1/(sqrt(2))x+sqrt(2)-1/(2sqrt(2))

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tangent of y=sqrt(2x+1),\at x= 1/2

tangent of

y = 2 x + 1, at x = \frac{1}{2}

y = \frac{1}{2} x + 2 - \frac{1}{2 2}

Solution steps

Find the tangent point:

(\frac{1}{2}, 2)

Find the slope of

y = 2 x + 1 : \frac{d y}{d x} = \frac{1}{2 x + 1}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(\frac{1}{2}, 2) : y = \frac{1}{2} x + 2 - \frac{1}{2 2}

y = \frac{1}{2} x + 2 - \frac{1}{2 2}

\int \frac{x ^{2} + 1}{2 x} d x

\int \frac{x}{x ^{3} + x} d x

n = 0 \sum \infty 2^{- \frac{n}{2}}

y = ln (5 x^{2} + 3 y^{2})

x \to 4 + lim (\frac{2 x}{x - 4})

What is the tangent of y=sqrt(2x+1),\at x= 1/2 ?
The tangent of y=sqrt(2x+1),\at x= 1/2 is y= 1/(sqrt(2))x+sqrt(2)-1/(2sqrt(2))