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Popular >

5y^'+y=-3

Solution

5 y^{^{'}} + y = - 3

Solution

y = e^{\frac{- t - c _{1}}{5}} - 3

Solution steps

5 y^{'} (t) + y = - 3

Solve separable ODE:

y = e^{\frac{- t - c _{1}}{5}} - 3

y = e^{\frac{- t - c _{1}}{5}} - 3

Graph

Popular Examples

tangent of f(x)=3x^4-8x^3+2 tangent of

f (x) = 3 x^{4} - 8 x^{3} + 2

derivative of 5e^{-2x}sin(3x)

\frac{d}{d x} (5 e^{- 2 x} sin (3 x))

maclaurin (1+x)^{-5/3}maclaurin

(1 + x)^{- \frac{5}{3}}

(\partial)/(\partial x)(ln(xy))

\frac{\partial}{\partial x} (ln (x y))

derivative of x^3e^{-x}

\frac{d}{d x} (x^{3} e^{- x})

Frequently Asked Questions (FAQ)

What is the solution for 5y^'+y=-3 ?
The solution for 5y^'+y=-3 is y=e^{(-t-c_{1})/5}-3