What is the derivative of x+y+1 ?

The derivative of x+y+1 is (dy)/(dx)+1

What is the first derivative of x+y+1 ?

The first derivative of x+y+1 is (dy)/(dx)+1

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\frac{d}{d x} (x + y + 1)

\frac{d y}{d x} + 1

Solution steps

\frac{d}{d x} (x + y + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d y}{d x} + \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 1 + \frac{d y}{d x} + 0

Simplify

= \frac{d y}{d x} + 1

f (x) = 2 e^{2 e^{x} + x}

\frac{3}{y ^{4}}

y^{^{''}} + 2 y^{^{'}} + y = 2^{- t}

\frac{cos ( x )}{x}

\int (\frac{e ^{x} - 1}{e ^{x} + 1}) d x

What is the derivative of x+y+1 ?
The derivative of x+y+1 is (dy)/(dx)+1
What is the first derivative of x+y+1 ?
The first derivative of x+y+1 is (dy)/(dx)+1