What is the derivative of f(x)=x^3+3x ?

The derivative of f(x)=x^3+3x is 3x^2+3

What is the first derivative of f(x)=x^3+3x ?

The first derivative of f(x)=x^3+3x is 3x^2+3

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derivative of

f (x) = x^{3} + 3 x

3 x^{2} + 3

Solution steps

\frac{d}{d x} (x^{3} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x) = 3

= 3 x^{2} + 3

x^{\frac{5}{7}}

f (x) = \frac{x + 9}{x - 9}

t^{2} y^{^{''}} - 5 t y^{^{'}} + 9 y = 0

x cos (3 x)

y^{^{'}} = x e^{y}, y (0) = 0

What is the derivative of f(x)=x^3+3x ?
The derivative of f(x)=x^3+3x is 3x^2+3
What is the first derivative of f(x)=x^3+3x ?
The first derivative of f(x)=x^3+3x is 3x^2+3