What is the integral of-9cos(x) ?

The integral of-9cos(x) is -9sin(x)+C

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integral of-9cos(x)

\int - 9 cos (x) d x

- 9 sin (x) + C

Solution steps

\int - 9 cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 9 \cdot \int cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= - 9 sin (x)

Add a constant to the solution

= - 9 sin (x) + C

x \to 3 lim (\frac{x - 1}{x ^{2} - 2})

\frac{d}{d x} (x^{6} + x)

x y^{2} d x = d y - x d x

x \to 0 lim (sin (\frac{4 π}{x}))

f (x) = 5 x^{2}