What is the integral of (5x^4+3x^2+2x) ?

The integral of (5x^4+3x^2+2x) is x^5+x^3+x^2+C

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integral of (5x^4+3x^2+2x)

\int (5 x^{4} + 3 x^{2} + 2 x) d x

x^{5} + x^{3} + x^{2} + C

Solution steps

\int 5 x^{4} + 3 x^{2} + 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 x^{4} d x + \int 3 x^{2} d x + \int 2 x d x

\int 5 x^{4} d x = x^{5}

\int 3 x^{2} d x = x^{3}

\int 2 x d x = x^{2}

= x^{5} + x^{3} + x^{2}

Add a constant to the solution

= x^{5} + x^{3} + x^{2} + C

\int 16 x ln (7 x) d x

\int_{0}^{\frac{π}{2}} 11 sin^{2} (2 x) d x

\int \frac{a ^{2} - x ^{2}}{x} d x

x y^{^{'}} + 2 y = 4 x^{2}

\frac{d}{d x} (\frac{- e ^{\frac{1}{x}}}{x ^{2}})

What is the integral of (5x^4+3x^2+2x) ?
The integral of (5x^4+3x^2+2x) is x^5+x^3+x^2+C