What is the derivative of f(x)=2x-1 ?

The derivative of f(x)=2x-1 is 2

What is the first derivative of f(x)=2x-1 ?

The first derivative of f(x)=2x-1 is 2

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derivative of

f (x) = 2 x - 1

2

Solution steps

\frac{d}{d x} (2 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (1)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 2 - 0

Simplify

= 2

\int 12 e^{3 x} d x

\int (1 - t) (2 + t^{2}) d t

\frac{d ^{2}}{d x ^{2}} (cot (2 x) + 3 x^{2})

\frac{d}{d x} (lo g_{2} (2 x))

\frac{d}{d x} (arccot (\frac{x}{2}))

What is the derivative of f(x)=2x-1 ?
The derivative of f(x)=2x-1 is 2
What is the first derivative of f(x)=2x-1 ?
The first derivative of f(x)=2x-1 is 2