What is the derivative of log_{2}(2x) ?

The derivative of log_{2}(2x) is 1/(ln(2)x)

What is the first derivative of log_{2}(2x) ?

The first derivative of log_{2}(2x) is 1/(ln(2)x)

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\frac{d}{d x} (lo g_{2} (2 x))

\frac{1}{ln ( 2 ) x}

Solution steps

\frac{d}{d x} (lo g_{2} (2 x))

Simplify

lo g_{2} (2 x) : lo g_{2} (x) + 1

= \frac{d}{d x} (lo g_{2} (x) + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (lo g_{2} (x)) + \frac{d}{d x} (1)

\frac{d}{d x} (lo g_{2} (x)) = \frac{1}{x ln ( 2 )}

\frac{d}{d x} (1) = 0

= \frac{1}{x ln ( 2 )} + 0

Simplify

= \frac{1}{ln ( 2 ) x}

\frac{d}{d x} (arccot (\frac{x}{2}))

f (x) = 7 - x^{2}

\int_{0}^{20} 1

\int 5 x^{2} sin (π x) d x

\frac{d}{d x} (ln ∣ x + 1 ∣)

What is the derivative of log_{2}(2x) ?
The derivative of log_{2}(2x) is 1/(ln(2)x)
What is the first derivative of log_{2}(2x) ?
The first derivative of log_{2}(2x) is 1/(ln(2)x)