What is the integral from 7 to 9 of 7/((x-8)^{10)} ?

The integral from 7 to 9 of 7/((x-8)^{10)} is diverges

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integral from 7 to 9 of 7/((x-8)^{10)}

\int_{7}^{9} \frac{7}{( x - 8 ) ^{10}} d x

diverges

Solution steps

\int_{7}^{9} \frac{7}{( x - 8 ) ^{10}} d x

Find undefined (singularity) points:

x = 8

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{7}^{8} \frac{7}{( x - 8 ) ^{10}} d x + \int_{8}^{9} \frac{7}{( x - 8 ) ^{10}} d x

\int_{7}^{8} \frac{7}{( x - 8 ) ^{10}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int \frac{( x ^{2} - x + 42 )}{x ^{3} + 7 x} d x

\frac{d}{d x} (- (x + 1) (x - 1)^{2})

f (x) = (\frac{x + 3}{x - 3})^{5}

\int (x + \frac{1}{x ^{3}}) d x

n = 1 \sum \infty \frac{1}{2} (0.3)^{n}

What is the integral from 7 to 9 of 7/((x-8)^{10)} ?
The integral from 7 to 9 of 7/((x-8)^{10)} is diverges