What is the derivative of (7x-8^5) ?

The derivative of (7x-8^5) is 35(7x-8)^4

What is the first derivative of (7x-8^5) ?

The first derivative of (7x-8^5) is 35(7x-8)^4

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\frac{d}{d x} ((7 x - 8)^{5})

35 (7 x - 8)^{4}

Solution steps

\frac{d}{d x} ((7 x - 8)^{5})

Apply the chain rule:

5 (7 x - 8)^{4} \frac{d}{d x} (7 x - 8)

= 5 (7 x - 8)^{4} \frac{d}{d x} (7 x - 8)

\frac{d}{d x} (7 x - 8) = 7

= 5 (7 x - 8)^{4} \cdot 7

Simplify

= 35 (7 x - 8)^{4}

\frac{\partial}{\partial x} (ln (2 y e^{x y}))

\frac{d}{d x} (\frac{x + 1}{x - 1})

\frac{d}{d x} (x^{x^{x}})

x \to \infty lim (\frac{2 ^{- x} - 2 ^{x}}{2 ^{- x} + 2 ^{x}})

\int \frac{2 x}{3 x ^{2} - 4} d x

What is the derivative of (7x-8^5) ?
The derivative of (7x-8^5) is 35(7x-8)^4
What is the first derivative of (7x-8^5) ?
The first derivative of (7x-8^5) is 35(7x-8)^4