What is the derivative of sqrt(x)+6\sqrt[3]{x} ?

The derivative of sqrt(x)+6\sqrt[3]{x} is 1/(2sqrt(x))+2/(x^{2/3)}

What is the first derivative of sqrt(x)+6\sqrt[3]{x} ?

The first derivative of sqrt(x)+6\sqrt[3]{x} is 1/(2sqrt(x))+2/(x^{2/3)}

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Popular >

\frac{1}{2 x} + \frac{2}{x ^{\frac{2}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{1}{2 x} + \frac{2}{x ^{\frac{2}{3}}}

\frac{d ^{2}}{d x ^{2}} (∣ x ∣)

\frac{d}{d t} (t e^{- 3 t})

\frac{d}{d x} (\frac{6 ( x ^{2} + 1 )}{( x ^{2} - 3 ) ^{3}})

e^{x}, x e^{x^{2}}, 0, 1

\frac{2 s + 5}{s ^{2} + 6 s + 34}

What is the derivative of sqrt(x)+6\sqrt[3]{x} ?
The derivative of sqrt(x)+6\sqrt[3]{x} is 1/(2sqrt(x))+2/(x^{2/3)}
What is the first derivative of sqrt(x)+6\sqrt[3]{x} ?
The first derivative of sqrt(x)+6\sqrt[3]{x} is 1/(2sqrt(x))+2/(x^{2/3)}