What is the limit as x approaches infinity of arctan(((1-x^2))/((1+x))) ?

The limit as x approaches infinity of arctan(((1-x^2))/((1+x))) is -pi/2

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limit as x approaches infinity of arctan(((1-x^2))/((1+x)))

x \to \infty lim (arctan (\frac{( 1 - x ^{2} )}{( 1 + x )}))

- \frac{π}{2}

Decimal

- 1.57079 \dots

Solution steps

x \to \infty lim (arctan (\frac{1 - x ^{2}}{1 + x}))

Simplify

arctan (\frac{1 - x ^{2}}{1 + x}) : arctan (- x + 1)

= x \to \infty lim (arctan (- x + 1))

Apply the Limit Chain Rule:

- \frac{π}{2}

= - \frac{π}{2}

\frac{d y}{d x} = 0.067 y (1 - \frac{y}{2800})

f (x) = x^{3}, (1, 1)

(2 x - y) + (2 y - x) y^{^{'}} = 0

\int \frac{5 x ^{2} + 11 x + 4}{x ^{3} + 3 x ^{2} + 3 x + 1} d x

\frac{d}{d x} (\frac{1}{( 4 x + 5 ) ^{2}})

What is the limit as x approaches infinity of arctan(((1-x^2))/((1+x))) ?
The limit as x approaches infinity of arctan(((1-x^2))/((1+x))) is -pi/2