What is the tangent of f(x)=sqrt(7x+2),\at x=2 ?

The tangent of f(x)=sqrt(7x+2),\at x=2 is y= 7/8 x+9/4

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tangent of f(x)=sqrt(7x+2),\at x=2

tangent of

f (x) = 7 x + 2, at x = 2

y = \frac{7}{8} x + \frac{9}{4}

Solution steps

Find the tangent point:

(2, 4)

Find the slope of

f (x) = 7 x + 2 : \frac{df ( x )}{d x} = \frac{7}{2 7 x + 2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{7}{8}

Find the line with slope m=

\frac{7}{8}

and passing through

(2, 4) : y = \frac{7}{8} x + \frac{9}{4}

y = \frac{7}{8} x + \frac{9}{4}

(0, 1), (5, 4)

(21 + x^{2}) y^{^{'}} - 2 x y = 0

\frac{\partial}{\partial y} (x y^{3} + x^{2} y^{2})

y^{^{'}} = 9.8 - \frac{3 y}{3.5}

x \to \infty lim (\frac{n ^{1.5}}{ln ( n )})

What is the tangent of f(x)=sqrt(7x+2),\at x=2 ?
The tangent of f(x)=sqrt(7x+2),\at x=2 is y= 7/8 x+9/4