What is the derivative of x^4-18x^2+81 ?

The derivative of x^4-18x^2+81 is 4x^3-36x

What is the first derivative of x^4-18x^2+81 ?

The first derivative of x^4-18x^2+81 is 4x^3-36x

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derivative of

x^{4} - 18 x^{2} + 81

4 x^{3} - 36 x

Solution steps

\frac{d}{d x} (x^{4} - 18 x^{2} + 81)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (18 x^{2}) + \frac{d}{d x} (81)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (18 x^{2}) = 36 x

\frac{d}{d x} (81) = 0

= 4 x^{3} - 36 x + 0

Simplify

= 4 x^{3} - 36 x

\frac{d}{d x} (- 3 tan^{3} (sin (x)))

(6 + x) (\frac{d y}{d x}) = 9 y

\frac{d}{d t} (e^{t} sin (t))

400 x^{10} + 40 x^{5} + 1

y^{^{'}} = \frac{4 sec ( y )}{( x - 6 ) ^{2}}

What is the derivative of x^4-18x^2+81 ?
The derivative of x^4-18x^2+81 is 4x^3-36x
What is the first derivative of x^4-18x^2+81 ?
The first derivative of x^4-18x^2+81 is 4x^3-36x