What is implicit (dy)/(dx),y=x^3+7 ?

The answer to implicit (dy)/(dx),y=x^3+7 is (dy)/(dx)=3x^2

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implicit (dy)/(dx),y=x^3+7

implicit derivative

\frac{d y}{d x}, y = x^{3} + 7

\frac{d y}{d x} = 3 x^{2}

Solution steps

y = x^{3} + 7

Treat

y

y (x)

Differentiate both sides:

\frac{d y}{d x} = 3 x^{2}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = 3 x^{2}

\frac{d y}{d x} = 3 x^{2}

\frac{d}{d x} (- x^{3})

\int cot (5 x) d x

- \frac{12}{s ^{2} - 5}

\int 17 θ sec^{2} (θ) d θ

y = e^{c x}

What is implicit (dy)/(dx),y=x^3+7 ?
The answer to implicit (dy)/(dx),y=x^3+7 is (dy)/(dx)=3x^2