What is the integral of (10)/(x^{0.5)} ?

The integral of (10)/(x^{0.5)} is 20sqrt(x)+C

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integral of (10)/(x^{0.5)}

\int \frac{10}{x ^{0.5}} d x

20 x + C

Solution steps

\int \frac{10}{x ^{0.5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int \frac{1}{x ^{0.5}} d x

Apply the Power Rule

: 2 x^{0.5}

= 10 \cdot 2 x^{0.5}

Simplify

10 \cdot 2 x^{\frac{1}{2}} : 20 x

= 20 x

Add a constant to the solution

= 20 x + C

y = x^{2} - 4 x, (7, 21)

4 - 3 x

\int (x^{2} - 18)^{8} (2 x) d x

\frac{d y}{d x}, 3 (x^{2} + y^{2})^{2} = 100 x y

\frac{d}{d x} (\frac{a ^{2} x}{( x + b ) ^{2}})

What is the integral of (10)/(x^{0.5)} ?
The integral of (10)/(x^{0.5)} is 20sqrt(x)+C