What is the limit as x approaches 6 of (x^2-3)/(x-6) ?

The limit as x approaches 6 of (x^2-3)/(x-6) is diverges

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limit as x approaches 6 of (x^2-3)/(x-6)

x \to 6 lim (\frac{x ^{2} - 3}{x - 6})

diverges

Solution steps

x \to 6 lim (\frac{x ^{2} - 3}{x - 6})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 6 + lim (\frac{x ^{2} - 3}{x - 6}) = \infty

x \to 6 - lim (\frac{x ^{2} - 3}{x - 6}) = - \infty

= diverges

x \to - 2 lim (2 x)

\frac{\partial}{\partial x} (\frac{2}{x - 3})

2 arcsin (x^{4})

x \to \infty lim (6 (1 + \frac{1}{x})^{x^{2}})

\frac{5 x ^{4}}{e ^{x}}

What is the limit as x approaches 6 of (x^2-3)/(x-6) ?
The limit as x approaches 6 of (x^2-3)/(x-6) is diverges