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Popular >

y^'=2e^{2x-y}

Solution

y^{^{'}} = 2 e^{2 x - y}

Solution

y = ln (e^{2 x} + c_{1})

Solution steps

y^{'} (x) = 2 e^{2 x - y}

Solve separable ODE:

y = ln (e^{2 x} + c_{1})

y = ln (e^{2 x} + c_{1})

Popular Examples

integral of xln(x-1)

\int x ln (x - 1) d x

derivative of (x^2)/(5+8x)derivative of

\frac{x ^{2}}{5 + 8 x}

derivative of f(x)=(x^5-x^3+3)derivative of

f (x) = (x^{5} - x^{3} + 3)

integral of 1/(x(5+3ln(x)))

\int \frac{1}{x ( 5 + 3 ln ( x ) )} d x

integral of 3^{-2x}

\int 3^{- 2 x} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=2e^{2x-y} ?
The solution for y^'=2e^{2x-y} is y=ln(e^{2x}+c_{1})