What is the solution for (y^')/(sqrt(y))=6x^2 ?

The solution for (y^')/(sqrt(y))=6x^2 is y=x^6+c_{1}x^3+(c_{1}^2)/4

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(y^')/(sqrt(y))=6x^2

\frac{y ^{^{'}}}{y} = 6 x^{2}

y = x^{6} + c_{1} x^{3} + \frac{c _{1}^{2}}{4}

Solution steps

\frac{y ^{'} ( x )}{y} = 6 x^{2}

Solve separable ODE:

y = x^{6} + c_{1} x^{3} + \frac{c _{1}^{2}}{4}

y = x^{6} + c_{1} x^{3} + \frac{c _{1}^{2}}{4}

\frac{d y}{d x}, y \cdot cos (x) = 2 x^{2} + 5 y^{2}

\int_{5}^{8} \frac{x}{x ^{2} + 6 x + 13} d x

\int_{\frac{1}{7}}^{5} 14 x ln (7 x) d x

f (x) = (x + 1) (x^{3} + x - 2)

\int_{1}^{4} \frac{x ^{2} + 6}{5 x - x ^{2}} d x

What is the solution for (y^')/(sqrt(y))=6x^2 ?
The solution for (y^')/(sqrt(y))=6x^2 is y=x^6+c_{1}x^3+(c_{1}^2)/4