What is the derivative of (1+x^3/(1-x^3)) ?

The derivative of (1+x^3/(1-x^3)) is (6x^2)/((1-x^3)^2)

What is the first derivative of (1+x^3/(1-x^3)) ?

The first derivative of (1+x^3/(1-x^3)) is (6x^2)/((1-x^3)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{1 + x ^{3}}{1 - x ^{3}})

\frac{6 x ^{2}}{( 1 - x ^{3} ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1 + x ^{3}}{1 - x ^{3}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 1 + x ^{3} ) ( 1 - x ^{3} ) - \frac{d}{d x} ( 1 - x ^{3} ) ( 1 + x ^{3} )}{( 1 - x ^{3} ) ^{2}}

\frac{d}{d x} (1 + x^{3}) = 3 x^{2}

\frac{d}{d x} (1 - x^{3}) = - 3 x^{2}

= \frac{3 x ^{2} ( 1 - x ^{3} ) - ( - 3 x ^{2} ) ( 1 + x ^{3} )}{( 1 - x ^{3} ) ^{2}}

Simplify

\frac{3 x ^{2} ( 1 - x ^{3} ) - ( - 3 x ^{2} ) ( 1 + x ^{3} )}{( 1 - x ^{3} ) ^{2}} : \frac{6 x ^{2}}{( 1 - x ^{3} ) ^{2}}

= \frac{6 x ^{2}}{( 1 - x ^{3} ) ^{2}}

\int 1 + 2 sin (θ) + sin^{2} (θ) d θ

sin (3 x)

\int 4 e^{c o s (x)} sin (x) d x

\int \frac{2 sin ( x )}{cos ( x )} d x

f (x) = tan (8 x)

What is the derivative of (1+x^3/(1-x^3)) ?
The derivative of (1+x^3/(1-x^3)) is (6x^2)/((1-x^3)^2)
What is the first derivative of (1+x^3/(1-x^3)) ?
The first derivative of (1+x^3/(1-x^3)) is (6x^2)/((1-x^3)^2)