What is the solution for y^'=((xy^2))/((1+x^2)) ?

The solution for y^'=((xy^2))/((1+x^2)) is y=-2/(ln(x^2+1)+c_{1)}

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y^'=((xy^2))/((1+x^2))

y^{^{'}} = \frac{( x y ^{2} )}{( 1 + x ^{2} )}

y = - \frac{2}{ln ( x ^{2} + 1 ) + c _{1}}

Solution steps

y^{'} (x) = \frac{( x y ^{2} )}{( 1 + x ^{2} )}

Solve separable ODE:

y = - \frac{2}{ln ( x ^{2} + 1 ) + c _{1}}

y = - \frac{2}{ln ( x ^{2} + 1 ) + c _{1}}

y^{^{''}} - 16 y^{^{'}} + 64 y = 0, y (0) = 1, y (1) = 0

x \to 0 lim ((1 - 2 x)^{\frac{3}{x}})

ln (361 sin^{2} (x))

\frac{\partial}{\partial y} (sin (- 2 x) cos (8 y))

(x + y) d x + x d y = 0

What is the solution for y^'=((xy^2))/((1+x^2)) ?
The solution for y^'=((xy^2))/((1+x^2)) is y=-2/(ln(x^2+1)+c_{1)}