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Popular >

f(t)=t^2+1

Solution

f (t) = t^{2} + 1

Solution

Domain : - \infty < t < \infty

Range : f (t) \geq 1

Y Intercepts : (0, 1)

Vertex : Minimum (0, 1)

Inverse : t - 1, - t - 1

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [1, \infty)

Solution steps

Domain of

t^{2} + 1 : - \infty < t < \infty

Range of

t^{2} + 1 : f (t) \geq 1

Axis interception points of

t^{2} + 1 :

Y Intercepts

: (0, 1)

Vertex of

t^{2} + 1 :

Minimum

(0, 1)

Inverse of

t^{2} + 1 : t - 1, - t - 1

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\int_{- 2}^{2} \frac{10}{x ^{2} - 2 x - 24} d x

integral of-e^x

\int - e^{x} d x

Frequently Asked Questions (FAQ)

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