What is the integral from 0 to 3.5 of 130x ?

The integral from 0 to 3.5 of 130x is 796.25

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integral from 0 to 3.5 of 130x

\int_{0}^{3.5} 130 x d x

796.25

Solution steps

\int_{0}^{3.5} 130 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 130 \cdot \int_{0}^{3.5} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{3.5}

= 130 [\frac{x ^{2}}{2}]_{0}^{3.5}

Simplify

= 130 [0.5 x^{2}]_{0}^{3.5}

Compute the boundaries:

6.125

= 130 \cdot 6.125

Simplify

= 796.25

\int_{0}^{2} (- x^{2} + 2 x)^{2} d x

\int t^{- 2} d t

2 (t - 3)^{2}

f (x) = x^{4} - 3 x^{2} + 2, at x = 1

\frac{d}{d x} (7 + cot (x) - 2 csc (x))

What is the integral from 0 to 3.5 of 130x ?
The integral from 0 to 3.5 of 130x is 796.25