What is (\partial)/(\partial t)(6e^xt+xt) ?

The answer to (\partial)/(\partial t)(6e^xt+xt) is 6e^x+x

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(\partial)/(\partial t)(6e^xt+xt)

\frac{\partial}{\partial t} (6 e^{x} t + x t)

6 e^{x} + x

Solution steps

\frac{\partial}{\partial t} (6 e^{x} t + x t)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial t} (6 e^{x} t) + \frac{\partial}{\partial t} (x t)

\frac{\partial}{\partial t} (6 e^{x} t) = 6 e^{x}

\frac{\partial}{\partial t} (x t) = x

= 6 e^{x} + x

\frac{d y}{d x} = \frac{x ^{7} - 2 y}{x}

\int_{0}^{2} x^{3} - 2 x^{2} d x

\frac{d}{d x} (\frac{3 x}{x + 2})

x \to 2 - lim (\frac{x + 3}{x - 2})

\int (sin^{2} (2 x)) (cos^{4} (2 x)) d x

What is (\partial)/(\partial t)(6e^xt+xt) ?
The answer to (\partial)/(\partial t)(6e^xt+xt) is 6e^x+x