What is the integral of csc(x)cot(x) ?

The integral of csc(x)cot(x) is -csc(x)+C

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integral of csc(x)cot(x)

\int csc (x) cot (x) d x

- csc (x) + C

Solution steps

\int csc (x) cot (x) d x

Apply u-substitution

: \int - 1 d u

= \int - 1 d u

Integral of a constant:

\int a d x = a x

= (- 1) u

Substitute back

u = csc (x)

= (- 1) csc (x)

Simplify

= - csc (x)

Add a constant to the solution

= - csc (x) + C

f (x) = - 8 x sin (4 x^{2} + 1)

\frac{d}{d x} (- f (x) sin (x) + g (x) cos (x))

\int \frac{x + 3}{5 - 4 x - x ^{2}} d x

\frac{d ^{2}}{d x ^{2}} (\frac{( x + b ) ( x - a )}{( x - b )})

What is the integral of csc(x)cot(x) ?
The integral of csc(x)cot(x) is -csc(x)+C