What is the derivative of sin(1+x^2) ?

The derivative of sin(1+x^2) is cos(1+x^2)*2x

What is the first derivative of sin(1+x^2) ?

The first derivative of sin(1+x^2) is cos(1+x^2)*2x

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\frac{d}{d x} (sin (1 + x^{2}))

cos (1 + x^{2}) \cdot 2 x

Solution steps

\frac{d}{d x} (sin (1 + x^{2}))

Apply the chain rule:

cos (1 + x^{2}) \frac{d}{d x} (1 + x^{2})

= cos (1 + x^{2}) \frac{d}{d x} (1 + x^{2})

\frac{d}{d x} (1 + x^{2}) = 2 x

= cos (1 + x^{2}) \cdot 2 x

y^{^{''}} + 2 y^{^{'}} + 5 y = e^{- x} sec (2 x)

\frac{d ^{2}}{d x ^{2}} (6 csc (x))

\frac{d}{d x} (x sinh (x^{2}))

\int \frac{1}{x ^{3} x ^{2} - 16} d x

f (x) = sin (2 x) + 2 cos (x)

What is the derivative of sin(1+x^2) ?
The derivative of sin(1+x^2) is cos(1+x^2)*2x
What is the first derivative of sin(1+x^2) ?
The first derivative of sin(1+x^2) is cos(1+x^2)*2x