What is the derivative of \sqrt[3]{t^2}+2sqrt(t^3) ?

The derivative of \sqrt[3]{t^2}+2sqrt(t^3) is (2t)/(3(t^2)^{2/3)}+3sqrt(t)

What is the first derivative of \sqrt[3]{t^2}+2sqrt(t^3) ?

The first derivative of \sqrt[3]{t^2}+2sqrt(t^3) is (2t)/(3(t^2)^{2/3)}+3sqrt(t)

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derivative of

\frac{2 t}{3 ( t ^{2} ) ^{\frac{2}{3}}} + 3 t

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d t} (2 t^{3}) = 3 t

= \frac{2 t}{3 ( t ^{2} ) ^{\frac{2}{3}}} + 3 t

\int_{0}^{1} \frac{2 x}{( x ^{2} + 2 ) ^{2}} d x

\frac{\partial}{\partial y} (8 e^{x} ln (y))

\frac{\partial}{\partial x} (7 e^{5 x})

f (x) = e^{x^{2} - 4}

x \to 2 lim ((x + 3)^{2})

What is the derivative of \sqrt[3]{t^2}+2sqrt(t^3) ?
The derivative of \sqrt[3]{t^2}+2sqrt(t^3) is (2t)/(3(t^2)^{2/3)}+3sqrt(t)
What is the first derivative of \sqrt[3]{t^2}+2sqrt(t^3) ?
The first derivative of \sqrt[3]{t^2}+2sqrt(t^3) is (2t)/(3(t^2)^{2/3)}+3sqrt(t)