What is the limit as x approaches 0+of 1/(e^x-1) ?

The limit as x approaches 0+of 1/(e^x-1) is infinity

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limit as x approaches 0+of 1/(e^x-1)

x \to 0 + lim (\frac{1}{e ^{x} - 1})

\infty

Solution steps

x \to 0 + lim (\frac{1}{e ^{x} - 1})

For

x

approaching

0

from the right

, x > 0 \Rightarrow e^{x} - 1 > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

y^{^{''}} + 16 y = sec^{2} (4 x)

\frac{x ^{3}}{6}

3 x y - 2 π cos (y) = 20 π, (6, π)

\int x^{2} sin (3 x + 2) d x

\int x (x + 5)^{7} d x

What is the limit as x approaches 0+of 1/(e^x-1) ?
The limit as x approaches 0+of 1/(e^x-1) is infinity