What is the tangent of f(x)=(25-0.075x)x,\at x=100 ?

The tangent of f(x)=(25-0.075x)x,\at x=100 is y=10x+750

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tangent of f(x)=(25-0.075x)x,\at x=100

tangent of

f (x) = (25 - 0.075 x) x, at x = 100

y = 10 x + 750

Solution steps

Find the tangent point:

(100, 1750)

Find the slope of

f (x) = (25 - 0.075 x) x : \frac{df ( x )}{d x} = - 0.15 x + 25

Compute the slope of

f (x) = (25 - 0.075 x) x

x = 100 : m = 10

Find the line with slope m=

10

and passing through

(100, 1750) : y = 10 x + 750

y = 10 x + 750

\int \frac{4 x ^{2} - 14 x - 6}{x ^{3} - 2 x ^{2} - 3 x} d x

n = 1 \sum \infty 1 - cos (\frac{1}{n})

x \to + 1 + lim (\frac{x - 1}{x - 1})

\frac{( y ^{^{'}} - e ^{- t} + 6 )}{y} = - 6

- 0.1 x^{3} + 600 x - 20

What is the tangent of f(x)=(25-0.075x)x,\at x=100 ?
The tangent of f(x)=(25-0.075x)x,\at x=100 is y=10x+750