What is area y=2x+1,y=13-x^2,x=-1,x=2 ?

The answer to area y=2x+1,y=13-x^2,x=-1,x=2 is 30

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area y=2x+1,y=13-x^2,x=-1,x=2

area

y = 2 x + 1, y = 13 - x^{2}, x = - 1, x = 2

30

Solution steps

Apply the area formula:

\int_{- 1}^{2} 2 x + 1 - (13 - x^{2}) d x

Solve

\int_{- 1}^{2} 2 x + 1 - (13 - x^{2}) d x : 30

The area is:

= 30

\int \frac{ln ( 9 x )}{x} d x

\int (1 - cos^{2} (x))^{2} sin (x) d x

s^{2} + 6

f (x) = 8 x^{3} - 2 x^{2} + 2 x, at x = 2

\int_{0}^{t} sin (2 s) d s

What is area y=2x+1,y=13-x^2,x=-1,x=2 ?
The answer to area y=2x+1,y=13-x^2,x=-1,x=2 is 30