What is the integral of (e^{-5ln(x)})/((1/(x^5))^2) ?

The integral of (e^{-5ln(x)})/((1/(x^5))^2) is (x^6)/6+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (e^{-5ln(x)})/((1/(x^5))^2)

\int \frac{e ^{- 5 l n (x)}}{( \frac{1}{x ^{5}} ) ^{2}} d x

\frac{x ^{6}}{6} + C

Solution steps

\int \frac{e ^{- 5 l n (x)}}{( \frac{1}{x ^{5}} ) ^{2}} d x

Simplify

\frac{e ^{- 5 l n (x)}}{( \frac{1}{x ^{5}} ) ^{2}} : x^{5}

= \int x^{5} d x

Apply the Power Rule

: \frac{x ^{6}}{6}

= \frac{x ^{6}}{6}

Add a constant to the solution

= \frac{x ^{6}}{6} + C

\int 6 x^{5} - 7 x^{4} - 6 x^{2} d x

\int cos (8)

\frac{d y}{d x} + \frac{( y ^{2} )}{x ^{2}} = 0

x \to - 1 + lim ((x + 1)^{0.5} + 2)

f (x) = (\frac{1}{2})^{x}

What is the integral of (e^{-5ln(x)})/((1/(x^5))^2) ?
The integral of (e^{-5ln(x)})/((1/(x^5))^2) is (x^6)/6+C