What is (\partial)/(\partial b)(mx+b) ?

The answer to (\partial)/(\partial b)(mx+b) is 1

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(\partial)/(\partial b)(mx+b)

\frac{\partial}{\partial b} (m x + b)

1

Solution steps

\frac{\partial}{\partial b} (m x + b)

Treat

m, x

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial b} (m x) + \frac{\partial}{\partial b} (b)

\frac{\partial}{\partial b} (m x) = 0

\frac{\partial}{\partial b} (b) = 1

= 0 + 1

Simplify

= 1

x \to 0 lim (e^{\frac{4}{x ^{2}}})

f (x) = 3 x^{4} (x - 3)^{2}

\frac{d}{d x} (- 3 sin (x) + cos (x))

y = 3^{- x^{2}}

\int e^{0.2 y} d y

What is (\partial)/(\partial b)(mx+b) ?
The answer to (\partial)/(\partial b)(mx+b) is 1