What is the limit as x approaches infinity of e^{1/x ln(2^x+3^x+5^x)} ?

The limit as x approaches infinity of e^{1/x ln(2^x+3^x+5^x)} is 5

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limit as x approaches infinity of e^{1/x ln(2^x+3^x+5^x)}

x \to \infty lim (e^{\frac{1}{x} l n (2^{x} + 3^{x} + 5^{x})})

5

Solution steps

x \to \infty lim (e^{\frac{1}{x} l n (2^{x} + 3^{x} + 5^{x})})

Apply the Limit Chain Rule:

5

= 5

\frac{d}{d x} (cos^{2} (1 - 2 x))

x y + y^{^{'}} = 166 x

(2 x y + 2 y^{2}) d x + (x^{2} + 4 x y) d y = 0, y (1) = 1

\int \frac{1}{x ^{2}} + 1 d x

n = 2 \sum \infty \frac{3}{5 ^{n}}

What is the limit as x approaches infinity of e^{1/x ln(2^x+3^x+5^x)} ?
The limit as x approaches infinity of e^{1/x ln(2^x+3^x+5^x)} is 5