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Popular >

y^'+2y=y^2

Solution

y^{^{'}} + 2 y = y^{2}

Solution

y = \frac{2}{- e ^{2 t + c_{1}} + 1}

Solution steps

y^{'} (t) + 2 y = y^{2}

Solve Bernoulli ODE:

y = \frac{2}{- e ^{2 t + c_{1}} + 1}

y = \frac{2}{- e ^{2 t + c_{1}} + 1}

Graph

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(x + 1) y^{^{'}} = x^{2} - y

Frequently Asked Questions (FAQ)

What is the solution for y^'+2y=y^2 ?
The solution for y^'+2y=y^2 is y= 2/(-e^{2t+c_{1)}+1}