What is (\partial)/(\partial x)(7x+6y+7xy) ?

The answer to (\partial)/(\partial x)(7x+6y+7xy) is 7y+7

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(\partial)/(\partial x)(7x+6y+7xy)

\frac{\partial}{\partial x} (7 x + 6 y + 7 x y)

7 y + 7

Solution steps

\frac{\partial}{\partial x} (7 x + 6 y + 7 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (7 x) + \frac{\partial}{\partial x} (6 y) + \frac{\partial}{\partial x} (7 x y)

\frac{\partial}{\partial x} (7 x) = 7

\frac{\partial}{\partial x} (6 y) = 0

\frac{\partial}{\partial x} (7 x y) = 7 y

= 7 + 0 + 7 y

Simplify

= 7 y + 7

\int cos (7 x) d x

x^{2} - 4 x + 1, 3 x - 5, 1, 4

\int \frac{2 y - x}{- ( y + x y )} d x

\int 5 ln (x^{2} + 5) d x

f (x) = (1 + 2 x)^{12}, at x = 0

What is (\partial)/(\partial x)(7x+6y+7xy) ?
The answer to (\partial)/(\partial x)(7x+6y+7xy) is 7y+7