What is the d/(dθ)(5sin(θ)) ?

The d/(dθ)(5sin(θ)) is 5cos(θ)

What is the first d/(dθ)(5sin(θ)) ?

The first d/(dθ)(5sin(θ)) is 5cos(θ)

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\frac{d}{d θ} (5 sin (θ))

5 cos (θ)

Solution steps

\frac{d}{d θ} (5 sin (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d θ} (sin (θ))

Apply the common derivative:

\frac{d}{d θ} (sin (θ)) = cos (θ)

= 5 cos (θ)

x \to 0 lim (\frac{1}{4} (4)^{4})

\int tan (3 t) d t

y^{^{'''}} + y^{^{''}} = x

\int \frac{3}{3 + e ^{x}} d x

y^{^{''}} + y^{^{'}} - 30 y = 0, y (0) = 2, y^{^{'}} (0) = - 2