What is area (4x)/(x^2+1),(2x)/(25) ?

The answer to area (4x)/(x^2+1),(2x)/(25) is -98/25+4ln(50)

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area (4x)/(x^2+1),(2x)/(25)

area

\frac{4 x}{x ^{2} + 1}, \frac{2 x}{25}

- \frac{98}{25} + 4 ln (50)

Decimal

11.72809 \dots

Solution steps

Apply the area formula:

\int_{- 7}^{7} \frac{4 x}{x ^{2} + 1} - \frac{2 x}{25} d x

Solve

\int_{- 7}^{7} \frac{4 x}{x ^{2} + 1} - \frac{2 x}{25} d x : - \frac{98}{25} + 4 ln (50)

The area is:

= - \frac{98}{25} + 4 ln (50)

\int_{0}^{\infty} x^{2} e^{- \frac{x}{2}} d x

x \to 0 + lim (x e^{s i n (\frac{π}{x})})

sin (x) π

\int \frac{6 ln ^{2} ( x )}{x} d x

\int \frac{- 4 x}{( 1 - 2 x ^{2} ) ^{2}} d x

What is area (4x)/(x^2+1),(2x)/(25) ?
The answer to area (4x)/(x^2+1),(2x)/(25) is -98/25+4ln(50)