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Popular >

y^'+xy^2=0

Solution

y^{^{'}} + x y^{2} = 0

Solution

y = - \frac{2}{- x ^{2} + c _{1}}

Solution steps

y^{'} (x) + x y^{2} = 0

Solve separable ODE:

y = - \frac{2}{- x ^{2} + c _{1}}

y = - \frac{2}{- x ^{2} + c _{1}}

Graph

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\int \frac{x}{x ^{4} - 16} d x

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\int sin (3 x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^'+xy^2=0 ?
The solution for y^'+xy^2=0 is y=-2/(-x^2+c_{1)}