What is the sum from n=1 to infinity of (4^n)/(4^n) ?

The sum from n=1 to infinity of (4^n)/(4^n) is diverges

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sum from n=1 to infinity of (4^n)/(4^n)

n = 1 \sum \infty \frac{4 ^{n}}{4 ^{n}}

diverges

Solution steps

n = 1 \sum \infty \frac{4 ^{n}}{4 ^{n}}

Simplify

= n = 1 \sum \infty 1

Every infinite sum of a non-zero constant diverges

= diverges

\frac{d}{d x} (4 x^{4} e^{x})

\int - x + tan (x) d x

y = sin (x) - cos (x)

\int \frac{1}{( 1 - x ^{2} )} d x

y^{^{'}} + 3 y = x e^{- 2 x} + e^{- 3 x}

What is the sum from n=1 to infinity of (4^n)/(4^n) ?
The sum from n=1 to infinity of (4^n)/(4^n) is diverges