What is the derivative of f(x)=ln(sqrt(x^2+3)) ?

The derivative of f(x)=ln(sqrt(x^2+3)) is x/(x^2+3)

What is the first derivative of f(x)=ln(sqrt(x^2+3)) ?

The first derivative of f(x)=ln(sqrt(x^2+3)) is x/(x^2+3)

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derivative of

f (x) = ln (x^{2} + 3)

\frac{x}{x ^{2} + 3}

Solution steps

\frac{d}{d x} (ln (x^{2} + 3))

Apply the chain rule:

\frac{1}{x ^{2} + 3} \frac{d}{d x} (x^{2} + 3)

= \frac{1}{x ^{2} + 3} \frac{d}{d x} (x^{2} + 3)

\frac{d}{d x} (x^{2} + 3) = \frac{x}{x ^{2} + 3}

= \frac{1}{x ^{2} + 3} \cdot \frac{x}{x ^{2} + 3}

Simplify

\frac{1}{x ^{2} + 3} \cdot \frac{x}{x ^{2} + 3} : \frac{x}{x ^{2} + 3}

= \frac{x}{x ^{2} + 3}

y = (x + 1) (x + 2)

\int cos (200 t n) d t

\int sin (20 x) cos (17 x) d x

x^{2} y^{^{'}} = y^{2} + 5 x y + 4 x^{2}

\frac{d}{d x} ((4 x^{2} - 8 x + 8) e^{- 6 x})

What is the derivative of f(x)=ln(sqrt(x^2+3)) ?
The derivative of f(x)=ln(sqrt(x^2+3)) is x/(x^2+3)
What is the first derivative of f(x)=ln(sqrt(x^2+3)) ?
The first derivative of f(x)=ln(sqrt(x^2+3)) is x/(x^2+3)