What is the limit as x approaches 0-of x^2sin(1/x) ?

The limit as x approaches 0-of x^2sin(1/x) is 0

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limit as x approaches 0-of x^2sin(1/x)

x \to 0 - lim (x^{2} sin (\frac{1}{x}))

0

Solution steps

x \to 0 - lim (x^{2} sin (\frac{1}{x}))

Apply the Squeeze Theorem:

0

= 0

\int e^{x} (\frac{1}{2} x^{2} + x) d x

t y^{^{'}} = y^{2} + 1

\int x cos (b x) d x

\frac{d y}{d x}, y = \frac{6}{x}

(2 x + ln (y)) d x + (\frac{x}{y}) d y = 0

What is the limit as x approaches 0-of x^2sin(1/x) ?
The limit as x approaches 0-of x^2sin(1/x) is 0