What is the solution for y^'=13.2-(6y)/(740-2t) ?

The solution for y^'=13.2-(6y)/(740-2t) is y=-6.6(t-370)+c_{1}(50653000-410700t+1110t^2-t^3)

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y^'=13.2-(6y)/(740-2t)

y^{^{'}} = 13.2 - \frac{6 y}{740 - 2 t}

y = - 6.6 (t - 370) + c_{1} (50653000 - 410700 t + 1110 t^{2} - t^{3})

Solution steps

y^{'} (t) = 13.2 - \frac{6 y}{740 - 2 t}

Solve linear ODE:

y = - 6.6 (t - 370) + c_{1} (50653000 - 410700 t + 1110 t^{2} - t^{3})

y = - 6.6 (t - 370) + c_{1} (50653000 - 410700 t + 1110 t^{2} - t^{3})

\frac{\partial}{\partial y} (x^{2} + 2 y^{2})

\frac{d y}{d x} = 4 x - y

\int \frac{x ^{2} - 3 x + 1}{x + 1} d x

\frac{\partial}{\partial y} (3 x e^{- 2 x y})

(\frac{d y}{d x}) = y - y

What is the solution for y^'=13.2-(6y)/(740-2t) ?
The solution for y^'=13.2-(6y)/(740-2t) is y=-6.6(t-370)+c_{1}(50653000-410700t+1110t^2-t^3)