What is the solution for 5e^{2x}(dy)/(dx)=-10 x/(y^2) ?

The solution for 5e^{2x}(dy)/(dx)=-10 x/(y^2) is y=\sqrt[3]{(6e^{-2x}x+3e^{-2x}+c_{1})/2}

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5e^{2x}(dy)/(dx)=-10 x/(y^2)

5 e^{2 x} \frac{d y}{d x} = - 10 \frac{x}{y ^{2}}

y = 3 \frac{6 e ^{- 2 x} x + 3 e ^{- 2 x} + c _{1}}{2}

Solution steps

5 e^{2 x} \frac{d y}{d x} = - 10 \frac{x}{y ^{2}}

Solve separable ODE:

y = 3 \frac{6 e ^{- 2 x} x + 3 e ^{- 2 x} + c _{1}}{2}

y = 3 \frac{6 e ^{- 2 x} x + 3 e ^{- 2 x} + c _{1}}{2}

f (x) = \frac{1}{2 x}, at x = 49

f (x) = 9 - \frac{4}{x ^{2}}

\frac{d}{d x} (x^{2} sec (\frac{1}{x}))

\int x^{3.4} - 2 x^{2 - 1} d x

\int_{- 2}^{0} 4 - x^{2} d x

What is the solution for 5e^{2x}(dy)/(dx)=-10 x/(y^2) ?
The solution for 5e^{2x}(dy)/(dx)=-10 x/(y^2) is y=\sqrt[3]{(6e^{-2x}x+3e^{-2x}+c_{1})/2}