What is the solution for t^2-t*y*y^'+y^2=0 ?

The solution for t^2-t*y*y^'+y^2=0 is y=tsqrt(2ln(t)+c_{1)},y=-tsqrt(2ln(t)+c_{1)}

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t^2-tyy^'+y^2=0

t^{2} - t \cdot y \cdot y^{^{'}} + y^{2} = 0

y = t 2 ln (t) + c_{1}, y = - t 2 ln (t) + c_{1}

Solution steps

t^{2} - t \cdot y \cdot y^{'} (t) + y^{2} = 0

Solve Bernoulli ODE:

y = t 2 ln (t) + c_{1}, y = - t 2 ln (t) + c_{1}

y = t 2 ln (t) + c_{1}, y = - t 2 ln (t) + c_{1}

\frac{t ^{6}}{( t ^{3} + 1 ) ^{2}}

\int 6 tan^{5} (x) sec^{2} (x) d x

x \to 0 - lim (\frac{8}{5 x ^{\frac{1}{5}}})

\int \frac{x ^{2}}{x - 5} d x

\frac{d y}{d x} = 0.2 \cdot y + 200

What is the solution for t^2-t*y*y^'+y^2=0 ?
The solution for t^2-t*y*y^'+y^2=0 is y=tsqrt(2ln(t)+c_{1)},y=-tsqrt(2ln(t)+c_{1)}