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Popular >

y^'t^4=0

Solution

y^{^{'}} t^{4} = 0

Solution

y = c_{1}

Solution steps

y^{'} (t) t^{4} = 0

Isolate

y^{'} (t) : y^{'} (t) = 0

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 0 d t

\int 0 d t = c_{1}

y = c_{1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'t^4=0 ?
The solution for y^'t^4=0 is y=c_{1}