What is area y=x^3-13x^2+36x,y=-x^3+13x^2-36x ?

The answer to area y=x^3-13x^2+36x,y=-x^3+13x^2-36x is 2521/6

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area y=x^3-13x^2+36x,y=-x^3+13x^2-36x

area

y = x^{3} - 13 x^{2} + 36 x, y = - x^{3} + 13 x^{2} - 36 x

\frac{2521}{6}

Decimal

420.16666 \dots

Solution steps

Apply the area formula:

\int_{0}^{9} x^{3} - 13 x^{2} + 36 x - (- x^{3} + 13 x^{2} - 36 x) d x

Solve

\int_{0}^{9} x^{3} - 13 x^{2} + 36 x - (- x^{3} + 13 x^{2} - 36 x) d x : \frac{2521}{6}

The area is:

= \frac{2521}{6}

\frac{d}{d x} (ln ∣ ln (3 x) ∣)

\frac{d}{d x} (e^{2 x - 4})

\frac{d}{d x} ((3 x)^{\frac{2}{3}} - 2)

f (x) = \frac{2 x}{x ^{2} + 4}

\int - 9 x^{2} sec (3 x^{3} + 1) tan (3 x^{3} + 1) d x

What is area y=x^3-13x^2+36x,y=-x^3+13x^2-36x ?
The answer to area y=x^3-13x^2+36x,y=-x^3+13x^2-36x is 2521/6