What is the first derivative of 8-3x ?

The first derivative of 8-3x is -3

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derivative of 8-3x

\frac{d}{d x} (8 - 3 x)

- 3

Solution steps

\frac{d}{d x} (8 - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8) - \frac{d}{d x} (3 x)

\frac{d}{d x} (8) = 0

\frac{d}{d x} (3 x) = 3

= 0 - 3

Simplify

= - 3

x \to \infty lim (x^{9})

\frac{2 x}{( 1 + x ^{2} ) ^{2}}

f (x) = \frac{x}{1 - ln ( x - 7 )}

cos (x), \frac{3 x}{2 π}, [0, 1]

y^{^{'}} = \frac{( ln ^{2} ( x ) )}{3 x}