What is the derivative of y=x^2-3x ?

The derivative of y=x^2-3x is 2x-3

What is the first derivative of y=x^2-3x ?

The first derivative of y=x^2-3x is 2x-3

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derivative of

y = x^{2} - 3 x

2 x - 3

Solution steps

\frac{d}{d x} (x^{2} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

= 2 x - 3

x \to - 3 - lim (h (x))

(1.7) (6.1)

\frac{d}{d x} (arctan (x + 1))

\frac{d}{d x} (26 (2 e^{x^{2}} x^{2} + e^{x^{2}}))

\int (1 + \frac{1}{x}) d x

What is the derivative of y=x^2-3x ?
The derivative of y=x^2-3x is 2x-3
What is the first derivative of y=x^2-3x ?
The first derivative of y=x^2-3x is 2x-3