What is the limit as x approaches+0 of xln(1/x) ?

The limit as x approaches+0 of xln(1/x) is Does not exist

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limit as x approaches+0 of xln(1/x)

x \to + 0 lim (x ln (\frac{1}{x}))

Does not exist

Solution steps

x \to 0 lim (x ln (\frac{1}{x}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (x ln (\frac{1}{x})) = 0

x \to 0 - lim (x ln (\frac{1}{x})) =

Does not exist

= Does not exist

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What is the limit as x approaches+0 of xln(1/x) ?
The limit as x approaches+0 of xln(1/x) is Does not exist