What is (\partial)/(\partial y)(y^2+x^2) ?

The answer to (\partial)/(\partial y)(y^2+x^2) is 2y

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(\partial)/(\partial y)(y^2+x^2)

\frac{\partial}{\partial y} (y^{2} + x^{2})

2 y

Solution steps

\frac{\partial}{\partial y} (y^{2} + x^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y^{2}) + \frac{\partial}{\partial y} (x^{2})

\frac{\partial}{\partial y} (y^{2}) = 2 y

\frac{\partial}{\partial y} (x^{2}) = 0

= 2 y + 0

Simplify

= 2 y

\int x^{2} sin (9 x) d x

\int \frac{x ^{2} + 1}{3 x ^{2} - x - 2} d x

t \to 0 + lim (t (ln (t))^{2})

\frac{\partial}{\partial x} (x^{3} + 3 x^{2} y)

x^{2} \frac{d y}{d x} = 4 x^{2} + 7 x y + 2 y^{2}

What is (\partial)/(\partial y)(y^2+x^2) ?
The answer to (\partial)/(\partial y)(y^2+x^2) is 2y